machine work
#44
Re: machine work
You're the one who were trying to argue that heat buildup wasn't a dominant factor in causing destructive detonation. And that engines have less heat buildup at peak power than they have at peak torque.
It's obvious you're not the one in the position to insult the thermodynamics knowledge of others.
It's obvious you're not the one in the position to insult the thermodynamics knowledge of others.
#45
Re: machine work
Originally Posted by baldur
You're the one who were trying to argue that heat buildup wasn't a dominant factor in causing destructive detonation. And that engines have less heat buildup at peak power than they have at peak torque.
It's obvious you're not the one in the position to insult the thermodynamics knowledge of others.
It's obvious you're not the one in the position to insult the thermodynamics knowledge of others.
#47
Re: machine work
your a ------- idiot. Your wrong, you know your wrong, but your trying to prove yourself right. But since you cant get it through your head..... right from the physics book
work done by a gas (combustion) = - integral from Vi to Vf of PdV where P is the pressure, d is the distance the gas is compressed, and V is the volume of the compressed gas.
now, the power of detonation P = W/delta t (change in time)
that is all
work done by a gas (combustion) = - integral from Vi to Vf of PdV where P is the pressure, d is the distance the gas is compressed, and V is the volume of the compressed gas.
now, the power of detonation P = W/delta t (change in time)
that is all
#48
Re: machine work
Oh brother. Let me summarize the facts for you who obviously don't understand and therefore resort to insults.
- Peak cylinder pressure is the highest at peak torque.
- Peak torque usually also happens within the window where the motor has peak thermal efficiency.
- Thermal efficiency is dictated by compression and the time available to complete combustion becomes a factor at some point. Friction also plays a part in brake mean efficiency.
- Detonation is caused by the pressure/heat of the mixture reaching autoignition points while there's still something left to burn.
At low revs the cylinder pressures are higher and there is lots of time for the combustion to complete. Combustion speed is roughly the same so the mixture will have to be ignited much later than at high revs to bring the peak pressure point in the right place of the power stroke.
At high revs (peak power and above) the cylinder pressures are in theory lower, but consider this. The engine is doing a whole lot more work, and thermal efficiency has gone down a little bit.
Engines run on events, each event nets a certain amount of joules. There's a lot more events happening every second, a lot more fuel and air being burned and a lot more heat to be dissipated.
What's also interesting to note is that with a turbo engine exhaust back pressures are higher than at peak torque and overall volumetric efficiency is lower so there's more residual exhaust gas in the cylinder in the inlet stroke, furthermore increasing charge air temperatures in the cylinder.
Hotter parts are also more vulnerable when detonation does happen because the heat reduces their tensile strength.
Lets look at the thermodynamics again. There's double the amount of heat generated in the engine at maximum revs than at lower revs. Simply the number of cycles per second is a lot higher. Heat transfer area and material stays the same. Heat transfer increases because the differential temperature between the combustion chamber and the outside is higher. In other words, the combustion chamber has to run hotter to dissipate the extra heat.
The heat doesn't have the courtesy of just leaving out the exhaust without touching anything else in the engine, like Joseph Davis likes to think. Yes, the residual heat from each cycle spends less time inside the cylinder at high revs, but the duty cycle at which there is combustion heat inside the cylinder just goes up as the revs go up.
I've run engines under a steady load, full throttle at both peak torque rpm and at peak power rpm. I'm comfortable sustaining peak torque for longer periods than peak power. It takes a manly cooling system (and oncoming wind) to keep the engine happy at peak power, much more than it takes at peak torque.
- Peak cylinder pressure is the highest at peak torque.
- Peak torque usually also happens within the window where the motor has peak thermal efficiency.
- Thermal efficiency is dictated by compression and the time available to complete combustion becomes a factor at some point. Friction also plays a part in brake mean efficiency.
- Detonation is caused by the pressure/heat of the mixture reaching autoignition points while there's still something left to burn.
At low revs the cylinder pressures are higher and there is lots of time for the combustion to complete. Combustion speed is roughly the same so the mixture will have to be ignited much later than at high revs to bring the peak pressure point in the right place of the power stroke.
At high revs (peak power and above) the cylinder pressures are in theory lower, but consider this. The engine is doing a whole lot more work, and thermal efficiency has gone down a little bit.
Engines run on events, each event nets a certain amount of joules. There's a lot more events happening every second, a lot more fuel and air being burned and a lot more heat to be dissipated.
What's also interesting to note is that with a turbo engine exhaust back pressures are higher than at peak torque and overall volumetric efficiency is lower so there's more residual exhaust gas in the cylinder in the inlet stroke, furthermore increasing charge air temperatures in the cylinder.
Hotter parts are also more vulnerable when detonation does happen because the heat reduces their tensile strength.
Lets look at the thermodynamics again. There's double the amount of heat generated in the engine at maximum revs than at lower revs. Simply the number of cycles per second is a lot higher. Heat transfer area and material stays the same. Heat transfer increases because the differential temperature between the combustion chamber and the outside is higher. In other words, the combustion chamber has to run hotter to dissipate the extra heat.
The heat doesn't have the courtesy of just leaving out the exhaust without touching anything else in the engine, like Joseph Davis likes to think. Yes, the residual heat from each cycle spends less time inside the cylinder at high revs, but the duty cycle at which there is combustion heat inside the cylinder just goes up as the revs go up.
I've run engines under a steady load, full throttle at both peak torque rpm and at peak power rpm. I'm comfortable sustaining peak torque for longer periods than peak power. It takes a manly cooling system (and oncoming wind) to keep the engine happy at peak power, much more than it takes at peak torque.
#49
Re: machine work
Originally Posted by baldur
What's also interesting to note is that with a turbo engine exhaust back pressures are higher than at peak torque and overall volumetric efficiency is lower so there's more residual exhaust gas in the cylinder in the inlet stroke, furthermore increasing charge air temperatures in the cylinder.
Originally Posted by baldur
The heat doesn't have the courtesy of just leaving out the exhaust without touching anything else in the engine, like Joseph Davis likes to think.
Originally Posted by baldur
Hotter parts are also more vulnerable when detonation does happen because the heat reduces their tensile strength.
Originally Posted by baldur
I've run engines under a steady load, full throttle at both peak torque rpm and at peak power rpm. I'm comfortable sustaining peak torque for longer periods than peak power. It takes a manly cooling system (and oncoming wind) to keep the engine happy at peak power, much more than it takes at peak torque.
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