Im dumb, Help me with my wideband question and I'll give you a discount!
Ok so I finally got my 3rd wideband (2 bad widebands in a row from Innovate). Well it works and I am datalogging with ecucontrol but I have to log the raw wideband voltage. I need a formula to convert the voltages into a/f ratio's. I havent taken math for years and can't remember.
Example: 0v = 7.35afr 5v = 22.39afr So I need to figure out what the incriments of voltage would correspond to as afr's.....like 3.78v would be ?? I would think there is a formula to work it out in excel, any input would be helpful, I'll throw a discount on any of my products to whoever can do this for me. ;) |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
make a X | Y table
EX: X | Y 0 | 0 1 | 4 2 | 8 x=4y, or 1v = 4a (in this example) dunno if that example was real or not. i got the table so i get points right? i gotta get back to work so i'll check back afterwords and get shopping ;) |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
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Re: Im dumb, Help me with my wideband question and I'll give you a discount!
Use the proportion formula.
X1=Y1*X2/Y1 example: X=3.78*22.39/5 X=16.93 The following is true only when using Innovate's factory settings. Where R=Reading in Volts and X= measured A/F X=(R*3.008)+7.35 Example: R=2.45 X=(2.45*3.008)+7.35 X=14.72 This should provide you with the values you are seeking. Good luck! ;D And where's my discount >:D ;D |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
this might be a retarded question, but why not just program the LM-1 to output .8 to .22 volts
where .8v = 8:1 .147 = 14.7:1 .22 = 22:1 |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
Yes you can program its output to any 0-5v voltage range...linear.
So you can use the slope/line formulas. Y =mX + B where M is the slope and B is the Y intercept m = (Y2 - Y1)/(X2 - X1) Remember 10th grade ;D So if you make .5v = .5 lambda and 4.5v = 1.5 lambda...what voltage is 1 lambda (14.7 AFRs)? m = (4.5 - .5) / (1.5 - .5) slope = 4 b = Y - mX b = 4.5 - 4(1.5) b = -1.5 Y = 4(1) - 1.5 Y = 2.5 So at approx 2.5v you will have 1 lambda or 14.7 I think I'm thinking straight today :P |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
Originally Posted by xenocron
Yes you can program its output to any 0-5v voltage range...linear.
So you can use the slope/line formulas. Y =mX + B where M is the slope and B is the Y intercept m = (Y2 - Y1)/(X2 - X1) Remember 10th grade ;D So if you make .5v = .5 lambda and 4.5v = 1.5 lambda...what voltage is 1 lambda (14.7 AFRs)? m = (4.5 - .5) / (1.5 - .5) slope = 4 b = Y - mX b = 4.5 - 4(1.5) b = -1.5 Y = 4(1) - 1.5 Y = 2.5 So at approx 2.5v you will have 1 lambda or 14.7 I think I'm thinking straight today :P |
Re: Im dumb, Help me with my wideband question and I'll give you a discount!
Originally Posted by xenocron
Yes you can program its output to any 0-5v voltage range...linear.
So you can use the slope/line formulas. Y =mX + B where M is the slope and B is the Y intercept m = (Y2 - Y1)/(X2 - X1) Remember 10th grade ;D So if you make .5v = .5 lambda and 4.5v = 1.5 lambda...what voltage is 1 lambda (14.7 AFRs)? m = (4.5 - .5) / (1.5 - .5) slope = 4 b = Y - mX b = 4.5 - 4(1.5) b = -1.5 Y = 4(1) - 1.5 Y = 2.5 So at approx 2.5v you will have 1 lambda or 14.7 I think I'm thinking straight today :P damn u guys are smart! |
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