cutting springs
01-31-2008, 07:48 PM
#41
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Join Date: Oct 2005
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Re: cutting springs
Originally Posted by wafflesincars
Dog, what are you talking about.
He isn't changing the diameter, nor is he increasing the range of the spring.
The resistance is based on the winding of the metal vs how many active coils there are. If he cuts off a set number of coils on a spring that has "x" resistance he isn't going to have the same spring rate, it's going to be lower.
He isn't changing the diameter, nor is he increasing the range of the spring.
The resistance is based on the winding of the metal vs how many active coils there are. If he cuts off a set number of coils on a spring that has "x" resistance he isn't going to have the same spring rate, it's going to be lower.
Do you even understand what is going on?
A 5" diameter spring with a wire diameter of 0.55" and 9 active coils = 162.25 lbs/inch.
A 5" diameter spring with a wire diameter of 0.55" and 7 active coils = 208.61 lbs/inch.
SO a higher number means a lower spring rate.
Hmmmmm.
I guess you do have it all figured out.
:1
01-31-2008, 07:59 PM
#42
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Join Date: Mar 2005
Posts: 723
Re: cutting springs
The common problem n00bs have is suspension binding. If you tighten all the UCA/LCA/Shock bolts/nuts while its in the air, the bushings want to remain at that ride height. Basicly pushing the car up along with the springs, rasiing ride height. Everything must be tightened with the suspension compressed to the right ride height. best thing to do is to set either end of the car onto blocks of wood (under the brake rotors), with a floor jack holding a little in case it slips off. Tighten everything, raise/bolt wheels on, then do the other end.
BTW if you DIE doing this, its not my fault. :1
BTW if you DIE doing this, its not my fault. :1
01-31-2008, 08:51 PM
#43
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Thread Starter
Join Date: Nov 2005
Posts: 551
Re: cutting springs
well if i had 500 bucks to throw away i would just buy something better....but i dont....im just tired of looking at the high *** bitch...ok so i wont cut them...i didnt think id have to pretty much cut the springs in half i thought it was gonna be like cut 1 1/2 coils off or something.....i dont go from having a nice smooth ride to having 5 inches of rock hard spring....i might as well just put a peice of pipe over my strut and ride on that ---- if its gonna be that shitty......
01-31-2008, 10:19 PM
#44
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Join Date: Oct 2003
Location: Your mom's panties
Posts: 3,696
Re: cutting springs
Dude.. do like VW bug guys have done for millions of years.... use a super tough chain to preload the springs... like attach the chain to the LCA and then up at the shock mount or something... lol.
02-01-2008, 10:46 AM
#45
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Join Date: Nov 2006
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Re: cutting springs
Originally Posted by snm95ls
You are obviously mentally challenged.
Do you even understand what is going on?
Do you even understand what is going on?
If you have a coil, with a set resistance and you REMOVE MATERIAL from it, the number of coils that are left do not require the same force to compress them.
You're neglecting elasticity and tensile strength.
The metal has a specific resistance value for how many coils are in the spring. Haven't you heard of Hooke's Law?
http://inventors.about.com/gi/dynami...b1/hooklaw.htm
02-01-2008, 11:27 AM
#46
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Join Date: Oct 2005
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Re: cutting springs
Originally Posted by wafflesincars
Seriously I must be, because your lexicon is baffling me.
If you have a coil, with a set resistance and you REMOVE MATERIAL from it, the number of coils that are left do not require the same force to compress them.
You're neglecting elasticity and tensile strength.
The metal has a specific resistance value for how many coils are in the spring. Haven't you heard of Hooke's Law?
http://inventors.about.com/gi/dynami...b1/hooklaw.htm
If you have a coil, with a set resistance and you REMOVE MATERIAL from it, the number of coils that are left do not require the same force to compress them.
You're neglecting elasticity and tensile strength.
The metal has a specific resistance value for how many coils are in the spring. Haven't you heard of Hooke's Law?
http://inventors.about.com/gi/dynami...b1/hooklaw.htm
Unless I am mistaken, Hooke's law is used primarily for determining position and load.
02-01-2008, 12:27 PM
#47
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Join Date: Aug 2003
Posts: 1,164
Re: cutting springs
More Coils = Lower Spring Rate.
The more coils there are the longer the wire is. The longer the wire is the less force it takes to deform it a certain distance. Think of it like trying to bend a 3 foot piece of steel to bending a 1.5 foot piece of steel. It takes a lot less effort to get a lot more deflection out of the 3 foot piece.
The more coils there are the longer the wire is. The longer the wire is the less force it takes to deform it a certain distance. Think of it like trying to bend a 3 foot piece of steel to bending a 1.5 foot piece of steel. It takes a lot less effort to get a lot more deflection out of the 3 foot piece.
02-01-2008, 12:59 PM
#48
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Join Date: Oct 2005
Posts: 0
Re: cutting springs
Originally Posted by rsmith2786
More Coils = Lower Spring Rate.
The more coils there are the longer the wire is. The longer the wire is the less force it takes to deform it a certain distance. Think of it like trying to bend a 3 foot piece of steel to bending a 1.5 foot piece of steel. It takes a lot less effort to get a lot more deflection out of the 3 foot piece.
The more coils there are the longer the wire is. The longer the wire is the less force it takes to deform it a certain distance. Think of it like trying to bend a 3 foot piece of steel to bending a 1.5 foot piece of steel. It takes a lot less effort to get a lot more deflection out of the 3 foot piece.
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