Figure this out and you'll get a free prize (physics question)
09-10-2004, 12:49 AM
#31
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Join Date: Jun 2003
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Re:Figure this out and you'll get a free prize (physics question)
Originally Posted by Kyle
I do alright with vectors. I start engineering classes next semester, I was supposed to go into math 115, that's algebra, but I took a review course and then tested into 191, calc 1.
yeah dude ---- algebra. They said I had to take pre-calc back in the day and I told them to ---- off and took alot of arguing but I didn't have to take it. I said "I'm paying the money, I'm not wasting my time with pre-calc so just let me in calc and if I fail its my fault"
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09-10-2004, 02:02 AM
#37
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Join Date: Dec 2002
Posts: 9,203
Re:Figure this out and you'll get a free prize (physics question)
Originally Posted by Kyle
this is ------- basic vector ----. don't make it too complicated. just turn all your information into forces and those forces will of course have directions, making them force vectors, then you just break down your vector going diagonal into horizontal and vetical and add it to your horizontal and vertical vectors. you might want to check my work since it's been 3 or 4 months since I raped the physics ap exam and got a 4, and it's not my *** so I didn't check ----.
By the way I think the answers are:
284N horizontal
-.0781 vertical
09-10-2004, 02:06 AM
#38
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Join Date: Oct 2003
Posts: 3,254
Re:Figure this out and you'll get a free prize (physics question)
cal 1 is fun kyle, just remember formulas and you will be fine.
what you have to remember in this situation is that they are polar coordinates at first, until you add the +/-2q turning them into cartesian coordinates (the have a magnitude.
Vx^ V
| /Vr
| /
|/_No _>
Vy
so Vx=|V| cosNo
Vy=|V| sinNo
r= square root of (x2+y2)
the easy thing to forget to do in the equasion is the -r
kyle very much surprises me. good on ya mate.
BTW whitey, what is this for in the first place?
what you have to remember in this situation is that they are polar coordinates at first, until you add the +/-2q turning them into cartesian coordinates (the have a magnitude.
Vx^ V
| /Vr
| /
|/_No _>
Vy
so Vx=|V| cosNo
Vy=|V| sinNo
r= square root of (x2+y2)
the easy thing to forget to do in the equasion is the -r
kyle very much surprises me. good on ya mate.
BTW whitey, what is this for in the first place?
